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Question: QUESTION 1
Consider a population of the jumping spider Marpissa
muscosa. It is polymorphic for a …


QUESTION 1

Consider a population of the jumping spider Marpissa
muscosa
. It is polymorphic for a 5 base-pair microsatellite.
Alleles with 7 and 4 copies are denoted by + and –,
respectively.

We found the following genotype counts in a sample of 47
individuals:

Genotype Count
+/+ 26
+/– 15
–/– 6

What would be expected number of +/+ homozygotes if the
population was in Hardy-Weinberg equilibrium and had the same
allele frequencies as the actual sample?

14

16

18

20

22

24

26

28

30

QUESTION 2

What is the value of the chi squared statistic testing whether the
population shows the genotype counts predicted under the hypothesis
of Hardy-Weinberg equilibrium?

0.3

1.3

2.3

3.3

4.3

5.3

6.3

7.3

QUESTION 1

Consider a population of the jumping spider Marpissa
muscosa
. It is polymorphic for a 5 base-pair microsatellite.
Alleles with 7 and 4 copies are denoted by + and –,
respectively.

We found the following genotype counts in a sample of 47
individuals:

Genotype Count
+/+ 26
+/– 15
–/– 6

What would be expected number of +/+ homozygotes if the
population was in Hardy-Weinberg equilibrium and had the same
allele frequencies as the actual sample?

14

16

18

20

22

24

26

28

30

0.5 points   

QUESTION 2

What is the value of the chi squared statistic testing whether the
population shows the genotype counts predicted under the hypothesis
of Hardy-Weinberg equilibrium?

0.3

1.3

2.3

3.3

4.3

5.3

6.3

7.3

0.5 points   

QUESTION 3

What do you conclude about the population?

Note: the critical value of the chi squared statistic at the 5% significance
level is 3.84.

chi squared < 3.84, so the population
does not deviate significantly (P > 0.05) from the
prediction of Hardy-Weinberg equilibrium. Therefore, the population
must satisfy one or more of the assumptions of Hardy-Weinberg
equilibrium.

chi squared < 3.84, so the population
does not deviate significantly (P > 0.05) from the
prediction of Hardy-Weinberg equilibrium. Therefore, the population
must violate one or more of the assumptions of Hardy-Weinberg
equilibrium.

chi squared < 3.84, so the population
does not deviate significantly (P > 0.05) from the
prediction of Hardy-Weinberg equilibrium. Therefore, we cannot
conclude anything about whether the population does or does not
satisfy any of the assumptions of Hardy-Weinberg equilibrium.

chi squared > 3.84, so the population
deviates significantly (P < 0.05) from the prediction
of Hardy-Weinberg equilibrium. Therefore, the population must
satisfy one or more of the assumptions of Hardy-Weinberg
equilibrium.

chi squared > 3.84, so the population
deviates significantly (P < 0.05) from the prediction
of Hardy-Weinberg equilibrium. Therefore, the population must
violate one or more of the assumptions of Hardy-Weinberg
equilibrium.

chi squared > 3.84, so the population
deviates significantly (P < 0.05) from the prediction
of Hardy-Weinberg equilibrium. Therefore, we cannot conclude
anything about whether the population does or does not satisfy any
of the assumptions of Hardy-Weinberg equilibrium.

QUESTION 4

Which of the following is an assumption of Hardy-Weinberg
equilibrium?

Every individual in the population always mates with an
individual with a different genotype.

Genotypes cannot mutate into other genotypes.

Some individuals in the population have a higher probability of
surviving and reproducing than others.

The total number of individuals (population size) changes from
generation to generation.

Grandparents, parents, and offspring can all be alive at the
same time.

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